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2. Fibonaccilike approach for the row 4, 4, 7, X, 103F(n) = a*F(n2) + b*F(n1) + c with F(0) = 4 and F(1) = 4 Applied accordingly it results: F(2) = a*F(0) + b*F(1) + c = 4a + 4b + c = 7 F(3) = a*F(1) + b*F(2) + c = 4a + 7b + c = X F(4) = a*F(2) + b*F(3) + c = 7a + Xb + c = 103 Solving this system of equations delivers the parameters depending on X: a = (X^{2} + 11X + 260) / 9 b = (X  7) / 3 c = (4X^{2}  56X  893) / 9 So you get solutions for wholenumbered X in the form of 3*k+7 (k≠0, since otherwise due to b=0 there is no link to F(1).) with wholenumbered continuations after the 103. back to the Mensapage In case of questions or suggestions just write an Email to me. 